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x^2+6x-41.25=0
a = 1; b = 6; c = -41.25;
Δ = b2-4ac
Δ = 62-4·1·(-41.25)
Δ = 201
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(6)-\sqrt{201}}{2*1}=\frac{-6-\sqrt{201}}{2} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(6)+\sqrt{201}}{2*1}=\frac{-6+\sqrt{201}}{2} $
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